-s^2-4s+45=0

Solution for -s^2-4s+45=0 equation:

-s^2-4s+45=0

We add all the numbers together, and all the variables

-1s^2-4s+45=0

a = -1; b = -4; c = +45;
Δ = b2-4ac
Δ = -42-4·(-1)·45
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-14}{2*-1}=\frac{-10}{-2}
=+5
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+14}{2*-1}=\frac{18}{-2}
=-9
$